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A projectile is shot at an angle of #pi/8 # and a velocity of # 16 m/s#. How far away will the projectile land?

Answer 1

Charles Aeschliman

#x_"maximum"=18,45" m"#

#v_i=16 " "m/s#

#alpha=pi/8# #2*alpha=2*pi/8=pi/4#

#sin (pi/4)=0,707# #g=9,81 N/(kg)# #x_"maximum"=(v_i^2*sin2alpha)/g#

#x_"maximum"=(16^2*0,707)/(9,81)#

#x_"maximum"=18,45" m"#

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Answer 2

William Audy

To find the horizontal distance the projectile will travel, you can use the formula for horizontal motion:

Horizontal distance = initial velocity * time * cos(angle)

First, calculate the time the projectile is in the air using the vertical motion equation:

time = (2 * initial velocity * sin(angle)) / acceleration due to gravity

Substitute the given values:

time = (2 * 16 * sin(pi/8)) / 9.8

Then, find the horizontal distance using the formula:

Horizontal distance = 16 * time * cos(pi/8)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.