# A projectile is shot at an angle of #pi/4 # and a velocity of # 12 m/s#. How far away will the projectile land?

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To find the horizontal distance traveled by the projectile, you can use the formula:

[ \text{Horizontal distance} = \frac{{\text{initial velocity}^2 \times \sin(2\theta)}}{g} ]

Where:

- Initial velocity ((v_0)) = 12 m/s
- Angle of projection ((\theta)) = (\pi/4)
- Acceleration due to gravity ((g)) = 9.8 m/s²

Plugging in the values:

[ \text{Horizontal distance} = \frac{{(12, \text{m/s})^2 \times \sin(2 \times \pi/4)}}{9.8, \text{m/s}^2} ]

[ \text{Horizontal distance} = \frac{{144 \times 1}}{9.8} ]

[ \text{Horizontal distance} ≈ 14.7, \text{m} ]

Therefore, the projectile will land approximately 14.7 meters away.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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