# A polygon has n sides. Three of its exterior angels are 70 degrees, 80 degrees and 90 degrees. The remaining #(n-3)# exterior angels are each 15 degrees. How many sides does this polygon have?

Polygon has

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To find the number of sides of the polygon, we can use the fact that the sum of all exterior angles of any polygon is always (360^\circ).

Given:

- Three exterior angles are (70^\circ), (80^\circ), and (90^\circ).
- The remaining (n-3) exterior angles are (15^\circ).

So, the sum of all exterior angles is: [ 70^\circ + 80^\circ + 90^\circ + (n-3) \times 15^\circ = 360^\circ ]

Solving for (n): [ 70^\circ + 80^\circ + 90^\circ + 15^\circ \times (n-3) = 360^\circ ] [ 240^\circ + 15^\circ \times (n-3) = 360^\circ ] [ 15^\circ \times (n-3) = 120^\circ ] [ n - 3 = \frac{120^\circ}{15^\circ} ] [ n - 3 = 8 ] [ n = 8 + 3 ] [ n = 11 ]

So, the polygon has (11) sides.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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