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A polygon has 6 sides. How would I find the measure of each exterior and interior angle?

Answer 1

Jayden Jackson

Use the interior sum formula ...

interior sum #=(6-2)xx180=720^o#

So, each interior angle #=720^o/6=120^o#

The sum of the exterior angles of any polygon is #360^o#

Each exterior angle #=360^o/6=60^o#

hope that helped

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Answer 2

Ella Armstrong

To find the measure of each exterior angle of a polygon with ( n ) sides, you can use the formula ( \text{Exterior Angle} = \frac{360^\circ}{n} ).

For a polygon with 6 sides, the measure of each exterior angle would be ( \frac{360^\circ}{6} = 60^\circ ).

To find the measure of each interior angle of a regular polygon with ( n ) sides, you can use the formula ( \text{Interior Angle} = \frac{(n - 2) \times 180^\circ}{n} ).

For a polygon with 6 sides, the measure of each interior angle would be ( \frac{(6 - 2) \times 180^\circ}{6} = \frac{4 \times 180^\circ}{6} = 120^\circ ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.