A pinball bangs against a bumper, giving the ball a speed of 52 cm/s. If the ball has a mass of 50.0 g, what is the ball's kinetic energy in joules?

Answer 1

I found: #K=6.76xx10^-3J#

We need first to change into #m/s# and #kg# to get: #52(cm)/s=52/100m/s=0.52m/s# and: #50g=50/1000kg=0.05kg# Kinrtic Energy will be: #K=1/2mv^2=1/2(0.05)(0.52)^2=6.76xx10^-3J#

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Answer 2

Nora Arzate

#6.76xx10^(-3)j#

We are aware of that.

#E_K=1/2mv^2#

here, #m=50gm=0.05kg# #v=52(cm)/s=0.52m/s#

so, #E_K=1/2*0.05*(0.52)^2# #=6.76xx10^(-3)j#

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Answer 3

Sebastian Acosta

To calculate the kinetic energy (KE) of the ball, we can use the formula: KE = 1/2 * mass * velocity^2. Plugging in the given values: mass = 50.0 g = 0.050 kg (since 1 kg = 1000 g) and velocity = 52 cm/s, we get: KE = 1/2 * 0.050 kg * (52 cm/s)^2. First, we need to convert the velocity from cm/s to m/s since the standard unit for velocity is meters per second. 1 cm/s = 0.01 m/s, so 52 cm/s = 0.52 m/s. Now, we can calculate the kinetic energy: KE = 1/2 * 0.050 kg * (0.52 m/s)^2. Plugging in the values and solving, we get: KE = 1/2 * 0.050 kg * (0.52 m/s)^2 = 0.5 * 0.050 kg * 0.2704 m^2/s^2 = 0.00676 J. Therefore, the ball's kinetic energy is approximately 0.00676 joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.