A parallelogram has sides A, B, C, and D. Sides A and B have a length of #6 # and sides C and D have a length of # 2 #. If the angle between sides A and C is #(3 pi)/8 #, what is the area of the parallelogram?

Answer 1

#11.088#

Area of a parallelogram is given by #axxbxxsintheta# where #a# and #b# are two sides and #theta# is angle between them.
Hence in this case Area is #6xx2xxsin(3pi/8)# or
#12xx0.924# or #11.088#.
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Answer 2

To find the area of the parallelogram, you can use the formula:

Area = base × height

In a parallelogram, any of its sides can be considered as the base. We'll take side A as the base. The height of the parallelogram can be found by dropping a perpendicular from a vertex to the opposite side.

Given:

  • Side A = 6
  • Side C = 2
  • Angle between sides A and C = ( \frac{3\pi}{8} )

Using trigonometry, you can find the height of the parallelogram by considering the sine of the angle between sides A and C.

Height = Side C × sin(angle between sides A and C)

Then, you can calculate the area using the formula mentioned above.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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