A parallelogram has sides A, B, C, and D. Sides A and B have a length of #2 # and sides C and D have a length of # 3 #. If the angle between sides A and C is #(7 pi)/12 #, what is the area of the parallelogram?

Answer 1

The area of the parallelogram is #5.8 # sq.unit.

Sides #(A=B)=s_1=2# , sides #(C=D)=s_2=3# and
#theta=(7pi)/12=105^0#
The area of the parallelogram as #A_p=s_1*s_2*sin theta #
Where #s_1=2,s_2=3,theta=(7pi)/12=105^0 # are the adjacent

sides and corner angle respectively.

#A_p=2*3*sin105~~5.8 # sq.unit.
The area of the parallelogram is #5.8 # sq.unit. [Ans]
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Answer 2

The area of the parallelogram can be calculated using the formula:

[ \text{Area} = \text{Base} \times \text{Height} ]

Given that sides A and C form a right angle, and knowing the lengths of sides A and C, the height of the parallelogram is ( 2 \sin(\frac{7\pi}{12}) ).

So, the area of the parallelogram is ( 2 \times 2 \times \sin(\frac{7\pi}{12}) ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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