A parallelogram has sides A, B, C, and D. Sides A and B have a length of #2 # and sides C and D have a length of # 7 #. If the angle between sides A and C is #(5 pi)/6 #, what is the area of the parallelogram?

Answer 1

Area of the parallelogram is #7#.

Area of a parallelogram with sides #a# and #b# and angle #theta# between them is given by #a*b*sintheta#

Hence area of parallelogram in the given case is

#2*7*sin((5pi)/6)#, but as #sin((5pi)/6)=sin(pi/6)=1/2#
Area of parallelogram is #2*7*1/2=7#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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