A model train with a mass of #9 kg# is moving along a track at #18 (cm)/s#. If the curvature of the track changes from a radius of #24 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

Answer 1

The centripetal force applied by the tracks change is #F_c=1.62N#.

Centripetal force #F_c=mv^2/r# As we know change in force '#DeltaF_c#' is inversely proportional to the change in the radius '#Deltar#'. So #Deltar=42cm-24cm=18cm# Conversion into metres for SI units #:.Deltar=18xx10^-2metre#. Similarly to the velocity#:.v=18xx10^-2m//s#. Substituting these values in above force equation we get, #F_c={(9kg)(18xx10^-2m//s)^2}/(18xx10^-2m)=1.62N#.
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Answer 2

Centripetal Force = (Mass * (Final Velocity)^2) / Radius

Centripetal Force (initial) = (9 kg * (0.18 m/s)^2) / 0.24 m

Centripetal Force (final) = (9 kg * (0.18 m/s)^2) / 0.42 m

Change in Centripetal Force = Centripetal Force (final) - Centripetal Force (initial)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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