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A model train with a mass of #3 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #5 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

Answer 1

Emily Abbate

The change in centripetal force is #0.304N#

Centripetal force is what

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=3kg#

The velocity of the train is #v=0.08ms^-1#

The tracks' respective radii are

#r_1=0.05m#

additionally

#r_2=0.24m#

The centripetal force's variance is

#DeltaF=F_2-F_1#

What are the centripetal forces?

#||F_1||=3*0.08^2/0.05=0.384N#

#||F_2||=3*0.08^2/0.24=0.08N#

#DeltaF=F_2-F_1=0.384-0.08=0.304N#

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Answer 2

Layla Ahmed

The centripetal force must change by 1.44 N.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.