A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #3 m#. If the train's kinetic energy changes from #4 j# to #5 j#, by how much will the centripetal force applied by the tracks change by?
The centripetal force will increase by a factor of 5/4.
I hope this helps, Steve
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The change in kinetic energy is ( \Delta KE = KE_f - KE_i = 5 J - 4 J = 1 J ). The centripetal force is given by ( F = \frac{{mv^2}}{r} ). Since the mass and radius remain constant, the change in centripetal force is directly proportional to the change in kinetic energy. Therefore, the change in centripetal force is ( \Delta F = \frac{{\Delta KE}}{r} = \frac{1 J}{3 m} ). So, the change in centripetal force applied by the tracks is approximately ( \frac{1}{3} ) Newtons.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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