# A model train with a mass of #2 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #5 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

The change in centripetal force is

Centripetal force is what

The centripetal force fluctuation is

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To calculate the change in centripetal force applied by the tracks, we can use the formula:

[ F_c = \frac{mv^2}{r} ]

Where:

- ( F_c ) is the centripetal force,
- ( m ) is the mass of the train (2 kg),
- ( v ) is the velocity of the train (9 cm/s), and
- ( r ) is the radius of the curvature of the track.

For the initial curvature with a radius of 5 cm:

[ F_{c1} = \frac{(2,kg) \times (9,cm/s)^2}{5,cm} ]

For the final curvature with a radius of 24 cm:

[ F_{c2} = \frac{(2,kg) \times (9,cm/s)^2}{24,cm} ]

The change in centripetal force can be calculated as:

[ \Delta F_c = F_{c2} - F_{c1} ]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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