Home > Physics > Circular Motion

A model train, with a mass of #12 kg#, is moving on a circular track with a radius of #3 m#. If the train's rate of revolution changes from #6 Hz# to #4 Hz#, by how much will the centripetal force applied by the tracks change by?

Answer 1

Emily Abbate

The variation in centripetal force is #=5684.9N#

The centripetal force is

#F=mr omega^2#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=12*3*((6-4)2pi)^2#

#=36*16*pi^2#

#=5684.9N#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Olivia Askew

The centripetal force applied by the tracks can be calculated using the formula:

[ F = m \cdot r \cdot (2 \pi f)^2 ]

Where:

( F ) is the centripetal force
( m ) is the mass of the train (12 kg)
( r ) is the radius of the circular track (3 m)
( f ) is the frequency of revolution (in Hz)

Using the initial frequency of revolution ( f_1 = 6 ) Hz:

[ F_1 = 12 \times 3 \times (2 \pi \times 6)^2 ]

And using the final frequency of revolution ( f_2 = 4 ) Hz:

[ F_2 = 12 \times 3 \times (2 \pi \times 4)^2 ]

To find the change in centripetal force, we subtract the initial force from the final force:

[ \Delta F = F_2 - F_1 ]

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.