A machine uses a force of 200 newtons to do 20,000 joules of work in 20 seconds. Find the distance the object moved and the power of the machine.

Answer 1
The answers are: #s=100m# and #P=1000W#.

These formulas are required in order to respond to the questions:

#L=vecF*vecs#: where the #*# is the scalar product;

additionally:

#P=L/t#

Thus:

#s=L/F=(20000J)/(200N)=100m#
(I supposed that the angle between #F and S# is 0);

additionally:

#P=(20000J)/(20s)=1000W#.
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Answer 2

To find the distance the object moved, you can use the formula:

Work = Force × Distance

So, rearranging the formula to solve for distance:

Distance = Work / Force

Distance = 20,000 J / 200 N

Distance = 100 meters

To find the power of the machine, you can use the formula:

Power = Work / Time

Power = 20,000 J / 20 s

Power = 1000 watts

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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