A linear graph contains the points of (0, -7), (1, -3), (2, 1), (3, 5), (4, 9). Is the function of the graph y = 4x - 7?
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Seeing the solution graphically:
Expanding on this answer, here it is graphically:
graph{(y-4x+7)((x-0)^2+(y+7)^2-.1)((x-1)^2+(y+3)^2-.1)((x-2)^2+(y-1)^2-.1)((x-3)^2+(y-5)^2-.1)((x-4)^2+(y-9)^2-.1)=0[-10,10,-5,5]}
scroll around on the graph to see all the points listed on the line.
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Yes, the function of the graph is y = 4x - 7.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write an equation of a point slope form passing through (-5,4) and parallel to the line whose equation is #4x-7y-8=0#?
- How do you write the equation in slope intercept form given (2, 2), (-1, 4)?
- How do you find the equation of the line that goes through #(- 4,3)# and #( 5,- 2)#?
- How do you write an equation of the line in standard form that is Parallel to 5y-4x=15 and through (10,6)?
- How do you write an equation of a line given point (3,3) and m=4/3?

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