A line segment is bisected by line with the equation # 6 y + 7 x = 4 #. If one end of the line segment is at #(2 ,4 )#, where is the other end?

Answer 1

End point coordinates #((6/7),-6)#

It is assumed that the intersecting line is a perpendicular bisector. #6y+7x=4# #y=-(7/6)x+(4/6)=-(7/6)x+(2/3)# Slope #= -(7/6)# Slope of the line segment #=-1/-(7/6)=6/7# Equation of line segment is #(y-4)=(6/7)(x-2)# #7y-28=6x-12# #7x-6y=16# Solving the equations we will get the coordinates of the mid point (intersection point). #14x=20# #x=(10/7)# #10-6y=16# #y=-1# Mid point coordinates # ((10/7),-1)# But mid point #(4+y1)/2=-1# & #(2+x1)/2=10/7# #y1=-6# & #x1=(20/7)-2=6/7# End point coordinates #((6/7),-6)#

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Answer 2

Sadie Allen

#(-(18)/5,-4/5)#

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Answer 3

Aaliyah Anderson

The other end of the line segment bisected by the line with the equation 6y + 7x = 4 can be found using the midpoint formula. Given one end of the line segment at (2, 4), the midpoint between the two ends of the line segment is at the intersection point of the line and the segment. Calculate the coordinates of this point by solving the system of equations formed by the line and the segment's midpoint condition.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.