A line segment is bisected by a line with the equation # - 3 y + 6 x = 5 #. If one end of the line segment is at #( 3 , 3 )#, where is the other end?

Question

A line segment is bisected by a line with the equation #  - 3  y  + 6  x   =   5  #.  If one end of the line segment is at #(     3  ,  3  )#, where is the other end?

Aurora Ayala · Accepted Answer

The other end will be any point on the line
#color(white)("XXX")-3y+6x=1#

To find one point that satisfy the required conditions, we could take the horizontal line through #(3,3)# and note that it intersects the given bisector equation at #(7/3,3)#

#(7/3,3)# is #2/3# to the left of #(3,3)#
The point horizontally #2/3# further to the left of #(7/3,3)#
is #(5/3,3)#

The bisector line, #-3y+6x=5# bisects the line segment between #(3,3)# and #(5/3,3)#

Furthermore any point, #P# on the line through #(5/3,3)# and parallel to the bisector line #-3y+6x=5#
will provide an endpoint that meets the requirement.

#-3y+6x=5# has a slope of #3#
So the required line will have a slope of #3# and pass through #(5/3,3)#
Using the slope-point form and then manipulating the derived equation into a similar form to that of the bisector line,
we get #-3y+6x=1#

Violet Aldrich · Answer

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Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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RearTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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RearrTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3)To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

RearrangingTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

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Rearranging theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the givenTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation toTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-interTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

TheTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) doesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lieTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie onTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

SinceTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6xTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joiningTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the twoTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. HenceTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negativeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocalTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we needTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to findTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line'sTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, whichTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection betweenTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

FromTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6xTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-sTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope formTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 andTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of aTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

ToTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To findTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 =To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = mTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we canTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solveTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the systemTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1),To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), whereTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which isTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, yTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1)To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joiningTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is aTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the twoTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpointsTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point onTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints:To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line andTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and mTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + bTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, whereTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where mTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we canTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope andTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can findTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and bTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b isTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-interTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-interceptTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

UsingTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve thisTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system toTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinatesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the otherTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3, 3) andTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3, 3) and theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3(3) + 6(3) = 5
-9 + 18 = 5
9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

1. The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
2. The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using the point (3, 3) and the slope -3/2, we get: y - 3 = -3/2(x - 3).

Expanding and rearranging, we get: y = -3/2x + 9.

Now, to find the other end of the line segment, we can set this equation equal to the equation of the line -3y + 6x = 5 and solve for the coordinates of the intersection point.

Substituting -3/2x + 9 for y in -3y + 6x = 5, we get: -3(-3/2x + 9) + 6x = 5.

Solving this equation will give us the x-coordinate of the other end of the line segment. Once we have the x-coordinate, we can substitute it back into either equation to find the corresponding y-coordinate.