# A line segment is bisected by a line with the equation # - 3 y + 6 x = 5 #. If one end of the line segment is at #( 3 , 3 )#, where is the other end?

The other end will be any point on the line

To find one point that satisfy the required conditions, we could take the horizontal line through

The point horizontally

is

The bisector line,

Furthermore any point,

will provide an endpoint that meets the requirement.

So the required line will have a slope of

Using the slope-point form and then manipulating the derived equation into a similar form to that of the bisector line,

we get

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To find the other end of the line segment bisected by the line -3y + 6x = 5, givenTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given thatTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that oneTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one endTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersectionTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection betweenTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is atTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between thisTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line andTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3),To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), weTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

GivenTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we firstTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given thatTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first findTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that oneTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one endTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment isTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is atTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3yTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y +To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x =To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), weTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we canTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substituteTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5.To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute theseTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. TheTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinatesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates intoTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-interTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept formTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line toTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to findTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find ifTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if itTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is yTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it liesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y =To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mxTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx +To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + bTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, whereTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

Given that one end of the line segment is at (3, 3), we can substitute these coordinates into the equation of the line to find if it lies on the line.

-3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where mTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3)To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

RTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

RearTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

RearrTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3)To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

RearrangingTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the givenTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation toTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-interTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

TheTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) doesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lieTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie onTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

SinceTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6xTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joiningTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the twoTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. HenceTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negativeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocalTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we needTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to findTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line'sTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, whichTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection betweenTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

FromTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Since the line bisects the line segment, the slope of the line segment joining the two endpoints is the negative reciprocal of the line's slope, which is -3/2.

From theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6xTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-sTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope formTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 andTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of aTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

ToTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To findTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

Since 9 ≠ 5, the point (3, 3) does not lie on the line -3y + 6x = 5. Hence, we need to find the point of intersection between the line -3y + 6x = 5 and the line segment.

To find this pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 =To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = mTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we canTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solveTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x -To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - xTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve the systemTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve the system ofTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1),To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

- The equation of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), whereTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

- The equation of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

To find this point, we can solve the system of equations formed by the given line and the line segment. We have:

- The equation of the line segment,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which isTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, yTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1)To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joiningTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is aTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the twoTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpointsTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point onTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints:To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y =To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line andTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx +To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and mTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + bTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m isTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b,To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, whereTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where mTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, weTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slopeTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we canTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope andTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can findTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and bTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b isTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equationTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the yTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the lineTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-interTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-interceptTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept. To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

UsingTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept. 2To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

From the point-slope form of the equation of a line, y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope, we can find the equation of the line segment.

Using theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept. 2.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the pointTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
- The equation of the given line: -3y + 6x = 5.

We can solve thisTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
- The equation of the given line: -3y + 6x = 5.

We can solve this system toTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the line segment, which is the line joining the two endpoints: y = mx + b, where m is the slope and b is the y-intercept.
- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinatesTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3,To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the otherTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3, To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of theTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3, 3To find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segmentTo find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3, 3) andTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3, 3) and theTo find the other end of the line segment bisected by the line -3y + 6x = 5, we first need to find the point of intersection between this line and the line segment.

-3(3) + 6(3) = 5 -9 + 18 = 5 9 = 5

- The equation of the given line: -3y + 6x = 5.

We can solve this system to find the coordinates of the other end of the line segment.To find the other end of the line segment bisected by the line -3y + 6x = 5, given that one end is at (3, 3), we first find the slope of the line -3y + 6x = 5. The slope-intercept form of the line equation is y = mx + b, where m is the slope.

Rearranging the given equation to slope-intercept form, we get: y = (2x + 5)/3.

The slope of the line is 2/3.

Using the point (3, 3) and the slope -3/2, we get: y - 3 = -3/2(x - 3).

Expanding and rearranging, we get: y = -3/2x + 9.

Now, to find the other end of the line segment, we can set this equation equal to the equation of the line -3y + 6x = 5 and solve for the coordinates of the intersection point.

Substituting -3/2x + 9 for y in -3y + 6x = 5, we get: -3(-3/2x + 9) + 6x = 5.

Solving this equation will give us the x-coordinate of the other end of the line segment. Once we have the x-coordinate, we can substitute it back into either equation to find the corresponding y-coordinate.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What is the orthocenter of a triangle with corners at #(4 ,9 )#, #(3 ,7 )#, and (1 ,1 )#?
- Natasha is constructing the bisector of PQ¯¯¯¯¯PQ¯. She has already constructed an arc as shown. What should Natasha do for her next step?
- A line segment is bisected by a line with the equation # 4 y - 2 x = 5 #. If one end of the line segment is at #( 7 , 3 )#, where is the other end?
- A triangle has corners at #(2 , 1 )#, ( 5 , 6)#, and #( 8 , 5 )#. What are the endpoints and lengths of the triangle's perpendicular bisectors?
- A triangle has corners A, B, and C located at #(1 ,1 )#, #(6 ,8 )#, and #(7 ,4 )#, respectively. What are the endpoints and length of the altitude going through corner C?

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