A line segment has endpoints at #(5 ,6 )# and #(6 , 1)#. The line segment is dilated by a factor of #2 # around #(4 , 2)#. What are the new endpoints and length of the line segment?

Answer 1

#(6,10),(8,0)#

#"let "A(5,6) ,B(6,1)" and "D(4,2)#
#" then "A'" and "B'" are the images of A and B under"# #"the dilatation"#
#rArrvec(DA')=color(red)(2)vec(DA)#
#rArrula'-uld=2(ula-uld)#
#rArrula'-uld=2ula-2uld#
#rArrula'=2ula-uld#
#color(white)(xxxx)=2((5),(6))-((4),(2))#
#color(white)(xxxx)=((10),(12))-((4),(2))=((6),(10))#
#rArrA'(6,10)#
#"similarly"#
#vec(DB')=color(red)(2)vec(DB)#
#rArrulb'-uld=2(ulb-uld)#
#rArrulb'=2ulb-uld#
#color(white)(xxxx)=2((6),(1))-((4),(2))=((8),(0))#
#rArrB'(8,0)#
#"to calculate length of segment use the "color(blue)"distance formula"#
#•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#
#"let "(x_1,y_1)=(6,10)" and "(x_2,y_2)=(8,0)#
#d=sqrt((8-6)^2+(0-10)^2)=sqrt104~~10.2" 1 dec. place"#
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Answer 2

The new endpoints of the line segment after dilation by a factor of 2 around the point (4, 2) can be found using the dilation formula. Let's denote the original endpoints as ( A(5, 6) ) and ( B(6, 1) ).

  1. Find the distance between the center of dilation (4, 2) and the original endpoints A and B. [ d_{A} = \sqrt{(5 - 4)^2 + (6 - 2)^2} = \sqrt{1^2 + 4^2} = \sqrt{17} ] [ d_{B} = \sqrt{(6 - 4)^2 + (1 - 2)^2} = \sqrt{2^2 + (-1)^2} = \sqrt{5} ]

  2. Multiply the distances ( d_{A} ) and ( d_{B} ) by the dilation factor, which is 2. [ d_{A_{new}} = 2 \times \sqrt{17} = 2\sqrt{17} ] [ d_{B_{new}} = 2 \times \sqrt{5} = 2\sqrt{5} ]

  3. Find the coordinates of the new endpoints by extending the original segment by the respective dilated distances along the same line. [ A_{new} = (4, 2) + \frac{{(5, 6) - (4, 2)}}{{d_{A}}} \times d_{A_{new}} ] [ B_{new} = (4, 2) + \frac{{(6, 1) - (4, 2)}}{{d_{B}}} \times d_{B_{new}} ]

Solving these equations will give the new endpoints ( A_{new} ) and ( B_{new} ). Then you can calculate the length of the line segment using the distance formula between the new endpoints.

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