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A line segment has endpoints at #(1 ,6 )# and #(6 ,7 )#. The line segment is dilated by a factor of #4 # around #(4 ,3 )#. What are the new endpoints and length of the line segment?

Answer 1

Sadie Allen

#(1,6) to (-8,15)#

#(6,7) to (12, 19) #

#l = 4 sqrt{26}#

I did the general case here.

#(p,q)=(4,3), quad r=4, quad (a,b)=(1,6), quad (c,d)=(6,7)#

#(a,b) to ( (1-r)p + ra, (1-r)q+ rb) #

#(1,6) to (-3(4)+4(1), -3(3) + 4(6)) = (-8,15)#

#(c,d) to ((1-r)p + rc, (1-r)q+ rd) #

#(6,7) to ( -3(4) + 4(6), -3(3) + 4(7)) = (12, 19) #

new length # l = r \sqrt{ (a-c)^2 + (b-d)^2 }#

#l = 4 \sqrt{(6-1)^2 + (7-6)^2} = 4 sqrt{26}#

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Answer 2

Wyatt Anderson

The new endpoints of the line segment after dilation by a factor of 4 around the point (4, 3) are:

Endpoint 1: (13, 18) Endpoint 2: (19, 19)

The length of the line segment after dilation is 10 units.

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