# A line passes through #(3 ,6 )# and #(4 ,7 )#. A second line passes through #(7 ,3 )#. What is one other point that the second line may pass through if it is parallel to the first line?

That is:

Which we can rearrange in slope intercept form as:

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To find a point that the second line may pass through if it is parallel to the first line, we need to use the slope formula. The slope of the first line passing through points (3,6) and (4,7) is:

m1 = (y2 - y1) / (x2 - x1) = (7 - 6) / (4 - 3) = 1 / 1 = 1

Since the second line is parallel to the first line, it will have the same slope. Now, we use the point-slope form of a line to find the equation of the second line passing through point (7,3) with slope 1:

y - y1 = m(x - x1) y - 3 = 1(x - 7) y - 3 = x - 7 y = x - 4

Now, we can choose any value for x to find the corresponding value of y. For instance, if we choose x = 8:

y = 8 - 4 y = 4

So, the second line may pass through the point (8, 4) if it is parallel to the first line passing through (3,6) and (4,7).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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