A line passes through #(2 ,8 )# and #( 1, 5 )#. A second line passes through #( 6, 8 )#. What is one other point that the second line may pass through if it is parallel to the first line?
We could verify that these pairs form parallel lines by checking that their slopes are equal.
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If the second line is parallel to the first line, it means that their slopes are equal.
To find the slope of the first line, we use the formula:
[ \text{Slope} = \frac{{\text{change in }} y}{{\text{change in }} x} ]
Given the points (2, 8) and (1, 5) on the first line:
[ \text{Change in } y = 8 - 5 = 3 ] [ \text{Change in } x = 2 - 1 = 1 ]
[ \text{Slope of the first line} = \frac{3}{1} = 3 ]
Since the second line is parallel to the first line, it must also have a slope of 3.
Given a point on the second line as (6, 8), we can find another point on the second line by moving 1 unit to the right and 3 units up (since the slope is 3):
[ x = 6 + 1 = 7 ] [ y = 8 + 3 = 11 ]
So, another point that the second line may pass through is (7, 11).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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