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A kayaker paddles with a power output of 490 W to maintain a steady speed of 1.50 m/s. What is the resistive force exerted by the water on the kayak?

Answer 1

Benjamin Asiedu

I found #163.3N# but check my method (whether it makes sense or not!).

Have a look:

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Answer 2

Layla Ahmed

#326.6"N"#

Using dimensional analysis:

Watts = #"N"."m.s"^(-1)#

#:.("N".cancel("m.s"^(-1)))/(cancel("m.s"^(-1)))="N"#

#:.F=490/1.5=326.6"N"#

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Answer 3

Adrian Ayala

To find the resistive force exerted by the water on the kayak, we can use the formula for power:

Power = Force × Velocity

We know the power output of the kayaker is 490 W and the velocity is 1.50 m/s. Rearranging the formula to solve for force:

Force = Power / Velocity

Substituting the given values:

Force = 490 W / 1.50 m/s

Calculate:

Force ≈ 326.67 N

So, the resistive force exerted by the water on the kayak is approximately 326.67 Newtons.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.