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A hill that has a 17.6% grade is one that rises 17.6 m vertically for every 100.0 m of distance in the horizontal direction. At what angle is such a hill inclined above the horizontal?

Answer 1

#10^circ#

If we draw the triangle with this property, its base is #100# m and its height is #17.6# m, so we know that the angle from the horizontal has the equation

#tan( theta) = 17.6/100#

i.e. #theta = arctan(0.176) = 9.98^circ#

With rounding errors, we report about a #10^circ# incline.

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Answer 2

Parker Abbott

The angle of inclination of a hill with a 17.6% grade is approximately 10 degrees above the horizontal.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.