# A gift basket with 3 different types of candles: tapers, pillars and jar candles. Candles cost $1, $4, $6 each respectively. Each basket has 8 candles costing $24. There are as many tapers as pillars and jar candles combined. How many of each do u need?

4 tapers, 2 pillars, 2 jars

Let t= # of tapers

Let= # of pillars

Let j= # of jars

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Let (x) represent the number of tapers, (y) represent the number of pillars, and (z) represent the number of jar candles.

Given:

- (x + y + z = 8) (since there are 8 candles in total)
- (x = y + z) (as there are as many tapers as pillars and jar candles combined)
- (1x + 4y + 6z = 24) (total cost of the candles is $24)

Using substitution or elimination, we can solve these equations simultaneously to find the values of (x), (y), and (z).

From equation (2), substitute (x = y + z) into equation (1) to get (y + z + y + z + z = 8), which simplifies to (2y + 3z = 8).

Now, we have two equations:

- (2y + 3z = 8)
- (1x + 4y + 6z = 24)

Solve these equations to find the values of (y) and (z). Then, use the value of (y) to find (x), as (x = y + z).

Once you find the values of (x), (y), and (z), you will know how many of each type of candle you need.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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