A gas sitting in a 5L container at 12 degrees celcius at 3atm, how many moles do you have?

Question

Natalie Anton · Accepted Answer

A bit over half a mole....

We just need to figure out the Ideal Gas equation. #n=(PV)/(RT)# #=(3*atmxx5.0*L)/(0.0821*(L*atm)/(K*mol)*(12+273.15)*K)# #=??*mol...#

Avery Adams · Answer

#0.641435498778218\approx 0.641\ ext{moles}# Using the ideal gas equation #PV=nRT# where #P# is absolute pressure of gas #V# is volume of gas #n# is number of moles of gas #R=8.314\ ext{J/mole K}# is universal gas constant. #T# is absolute temperature of gas #n=(PV)/(RT)# establishing the values #P=3\ "atm"=3 xx 101325\ "Pa"#, #V=5\ "L"=5 xx 10^{-3}\ "m"^3# #R=8.314 \ ext{J/mole K}# #T=12^0 "C"=12+273=285\ "K"# We obtain the quantity of moles. #n=\frac{3 imes 101325 imes 5 imes 10^{-3} }{8.314 imes 285}# #=0.641435498778218\ ext{moles}# #\approx 0.641\ ext{moles}#

Jeremiah Adams · Answer

You have #"0.6 mol"# of gas.

Use the ideal gas law equation: #PV=nRT#, where: #P# is pressure, #V# is volume, #n# is moles, #R# is the gas constant, and #T# is the temperature in Kelvins. Known #P="3 atm"# #V="5 L"# #R="0.08206 L atm K"^(-1) "mol"^(-1)# #T="12"^@"C + 273.15"="285 K"# Unknown #n# Solution Rearrange the equation to isolate moles. Plug in the known values and solve. #n=(PV)/(RT)# #n=(3color(red)cancel(color(black)("atm"))xx5color(red)cancel(color(black)("L")))/(0.08206color(red)cancel(color(black)("L")) color(red)cancel(color(black)("atm")) color(red)cancel(color(black)("K"))^(-1) "mol"^(-1)xx285color(red)cancel(color(black)("K")))="0.6 mol"# (rounded to one significant figure)

Peyton Adams · Answer

undefined To find the number of moles of gas in the container, we can use the ideal gas law equation:

n = (PV) / (RT)

Where:
n = number of moles
P = pressure (in atm)
V = volume (in liters)
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (in Kelvin)

First, we need to convert the temperature from Celsius to Kelvin:

T(K) = T(°C) + 273.15

T(K) = 12°C + 273.15 = 285.15 K

Now, we can plug the values into the formula:

n = (3 atm * 5 L) / (0.0821 L·atm/mol·K * 285.15 K)

Calculating this gives:

n ≈ 0.624 moles