Home > Chemistry > Gas Pressure

A gas sample has a volume of 225 mL at 122 kPa. What will its volume be at 101 kPa?

Answer 1

Naomi Aronson

At constant #T#, #P_1V_1=P_2V_2#

Thus #V_2# #=# #(P_1V_1)/P_2# #=# #(225*mLxx122*kPa)/(101*kPa)# #=# #??mL#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Natalie Anton

To find the new volume, you can use the combined gas law equation:

( P_1V_1 = P_2V_2 )

Where: ( P_1 = 122 , \text{kPa} ) (initial pressure) ( V_1 = 225 , \text{mL} ) (initial volume) ( P_2 = 101 , \text{kPa} ) (final pressure, given) ( V_2 ) (final volume, what we're solving for)

Rearranging the equation to solve for ( V_2 ), we get:

( V_2 = \frac{{P_1V_1}}{{P_2}} )

Substituting the given values:

( V_2 = \frac{{122 , \text{kPa} \times 225 , \text{mL}}}{{101 , \text{kPa}}} )

( V_2 = \frac{{27450}}{{101}} , \text{mL} )

( V_2 ≈ 271.79 , \text{mL} )

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.