A furlong is a distance of 220 yards. A fortnight is a time period of two weeks. A race horse is running at a speed of 5.00 yards per second. What is his speed in furlongs per fortnight?

Answer 1

Speed of race horse is #27490.91# furlongs per fortnight.

There are #14# days in a fortnight and hence #14xx24=336# hours
i.e. #336xx60=20160# minutes or #20160xx60=1209600# seconds
As the race horse runs at a speed of #5.00# yards per second,
heruns #5xx1209600=6048000# yards in a fotnight.
There are #220# yards in a furlong,
Therefore #6048000# yards is equivalent to
#6048000/220=27490.91# furlongs (rounded to #2dp#)
Hence, speed of race horse is #27490.91# furlongs per fortnight.
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Answer 2

To find the speed of the race horse in furlongs per fortnight, you need to convert the speed from yards per second to furlongs per fortnight. Here are the steps:

  1. Convert the speed from yards per second to furlongs per second.
  2. Convert the time period from seconds to fortnights.

Let's proceed with the calculations:

  1. Convert the speed from yards per second to furlongs per second: Given: 1 furlong = 220 yards [ \text{Speed in furlongs per second} = \frac{\text{Speed in yards per second}}{220} ] [ \text{Speed in furlongs per second} = \frac{5.00 , \text{yards per second}}{220} ] [ \text{Speed in furlongs per second} = \frac{5.00}{220} ] [ \text{Speed in furlongs per second} ≈ 0.0227 , \text{furlongs per second} ]

  2. Convert the time period from seconds to fortnights: Given: 1 fortnight = 14 days = ( 14 \times 24 \times 60 \times 60 ) seconds [ \text{Time in fortnights} = \frac{\text{Time in seconds}}{14 \times 24 \times 60 \times 60} ] [ \text{Time in fortnights} = \frac{2 \times 7 \times 24 \times 60 \times 60}{14 \times 24 \times 60 \times 60} ] [ \text{Time in fortnights} = \frac{2}{14} ] [ \text{Time in fortnights} = \frac{1}{7} ]

Now, multiply the speed in furlongs per second by the time in fortnights to get the speed in furlongs per fortnight: [ \text{Speed in furlongs per fortnight} = \text{Speed in furlongs per second} \times \text{Time in fortnights} ] [ \text{Speed in furlongs per fortnight} = 0.0227 , \text{furlongs per second} \times \frac{1}{7} ] [ \text{Speed in furlongs per fortnight} ≈ 0.00324 , \text{furlongs per fortnight} ]

Therefore, the speed of the race horse is approximately 0.00324 furlongs per fortnight.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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