A full bucket of water weighs eight kilograms. If the water weighs five times as much as the empty bucket, how much do the water weigh?
6.67 kg
Convert the statement into an algebraic equation and solve for the desired value. Sum and plus = addition, Times = multiplication. Same = equals use ‘x’ as the unknown value.
Full Bucket = Water + Bucket ; Water = 5*Bucket
8 = 5Bucket + Bucket = 6Bucket ; Bucket = 8/6 = 1.33 ;
Water = 5*1.33 = 6.67 kg
CHECK: 1.33 + 6.67 = 8 Correct.
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If the full bucket of water weighs 8 kilograms and the water weighs 5 times as much as the empty bucket, then the weight of the water alone is:
[ \text{Weight of water} = 8 , \text{kg} \times (5 - 1) = 8 , \text{kg} \times 4 = 32 , \text{kg} ]
So, the water alone weighs 32 kilograms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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