A frame of movie film is 35 mm wide and 26.25 mm high. The film projects an image 8 m wide. How high is the image?

Answer 1

The image is #6 m# high.

Using optical lenses, the projector will amplify the size of the image resulting from shining a bright light through the film directed towards a viewing screen.

Given: The film frame is 35 mm W and 26.25 mm H The image is 8 m W and Unknown H

The optics have been carefully constructed to project an image size that is directly proportional to the film frame size so we can equate the height and width of one to the other.

#(35 mm W)/(8 m W) = (26.25 mm H)/(U H)#

Note that we keep the two widths and the two heights together so they remain relative to each other.

Clearing out the units, we have #m# left over, so the answer will be in #m#
#(35)/(8 m ) = (26.25)/(U)#
#35U = 8 m xx 26.25#
#U = (8m xx 26.25)/35#
#U = 6 m#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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