A force of 63N acting upon a given object results in an acceleration of 9 m/s^2. If the magnitude of the force acting upon the same object is changed to 28 N, what will the object's acceleration become?

Question

Nathan Ashcroft · Accepted Answer

#"4 m/s"^2#

Use Newton's #2^(nd)# Law:

#F= ma #

Since the mass of the object doesn't change,

#m = F/a = F_1/a_1 = F_2/a_2#

then solve for #a_2#:

#a_2= F_2/F_1*a_1#

#a_2= "28 N"/"63 N" * "9 m/s"^2 = "4 m/s"^2#

Note: Less force implies less acceleration; the answer is consistent. Checked.

Charles Aeschliman · Answer

undefined Using Newton's second law of motion, we can determine the acceleration of the object when the force is changed.

$ F = m \times a $

Given:
$ F_1 = 63N $
$ a_1 = 9 m/s^2 $

$ F_2 = 28N $

Rearranging the equation:
$ a_2 = \frac{F_2}{m} $

Substituting the values:
$ a_2 = \frac{28N}{m} $

Using the relation between force and acceleration:
$ a_1 = \frac{63N}{m} $

Since $a_1$ is given as $9 m/s^2$, we can solve for $m$:
$ m = \frac{63N}{9 m/s^2} $

$ m = 7kg $

Now substituting $m$ into $a_2$:
$ a_2 = \frac{28N}{7kg} $

$ a_2 = 4 m/s^2 $

Therefore, when the force acting upon the object is changed to $28N$, the object's acceleration becomes $4 m/s^2$.