A flask contains 85.5 g #C_12H_22O_11# (sucrose) in 1.00 liters of solution. What is the molarity?

Question

Noah Aldrich · Accepted Answer

#"molarity" = 0.250M#

We're asked to find the molar concentration (molarity) of a sucrose solution, given the volume of solution and mass of solute.

The equation for molarity is

#"molarity" = "mol solute"/"L soln"#

We're given the volume is #1.00# #"L"#, so we just need to find the moles of solute (we're given grams) via the molar mass of sucrose (#342.30# #"g/mol"#):

#85.5cancel("g sucrose")((1color(white)(l)"mol sucrose")/(342.30cancel("g sucrose"))) = color(red)(0.250# #color(red)("mol sucrose"#

Therefore, we have

#"molarity" = (color(red)(0.250color(white)(l)"mol sucrose"))/(1.00color(white)(l)"L soln") = color(blue)(0.250M#

Caleb Adams · Answer

undefined The molarity (M) of a solution is calculated by dividing the number of moles of solute by the volume of the solution in liters.

To find the molarity of the sucrose solution:

1. Calculate the number of moles of sucrose (C12H22O11) using its molar mass.
2. Determine the volume of the solution in liters.
3. Use the formula Molarity (M) = Moles of solute / Volume of solution (in liters).

Molar mass of sucrose (C12H22O11):
12(12.01 g/mol) + 22(1.01 g/mol) + 11(16.00 g/mol) = 342.34 g/mol

Number of moles of sucrose:
85.5 g / 342.34 g/mol = 0.2495 moles

Volume of solution: 1.00 liters

Molarity (M) = 0.2495 moles / 1.00 liters = 0.2495 M