# A diwali rocket is ejecting 50 g of gases at velocity of 400m/s .the accelerating force on the rocket will be...???

I believe you typed the question incorrectly.

The idea here is that the rocket is moving at a constant speed, which corresponds to the constant rate at which the gases are being ejected.

The acceleration of an object moving at a constant speed is equal to zero because acceleration is the derivative of speed with respect to time.

The rocket's mass is not constant, despite its constant speed, which suggests that its momentum will also be variable.

Momentum is defined as, assuming the rocket flies straight upward,

The rocket's mass changes with respect to time, which causes the rocket's momentum to change as well.

Newton's Second Law states that an object's momentum changes at a rate proportional to the force acting on it.

Utilize the product rule to set this function apart.

Thus, it follows that

Therefore, the accelerating force will be

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To find the accelerating force on the rocket, you can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration:

[F = ma]

In this case, the mass (m) of the gases ejected is 50 g, which is 0.05 kg after converting to kilograms. The velocity (v) of the gases is 400 m/s. Since the gases are being ejected from the rocket, the velocity of the gases is the same as the velocity of the rocket's exhaust, which is the velocity of the rocket relative to the ground.

Given that the velocity (v = 400 , \text{m/s}) and the mass (m = 0.05 , \text{kg}), you can calculate the accelerating force ((F)).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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