A container with a volume of #5 L# contains a gas with a temperature of #360^o K#. If the temperature of the gas changes to #640^o K# without any change in pressure, what must the container's new volume be?

Answer 1

Nora Arzate

#=8.89L#

Applying Charl's law #V_2/V_1=T_2/T_1# #V_2=V_1xxT_2/T_1=5xx640/360=8.89L#

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Answer 2

Leo Abeyta

According to Charles's Law, for a given amount of gas at constant pressure, the volume of the gas is directly proportional to its temperature in Kelvin.

V1 / T1 = V2 / T2

Given: Initial volume (V1) = 5 L Initial temperature (T1) = 360 K Final temperature (T2) = 640 K

Solve for the final volume (V2): V2 = V1 * (T2 / T1) V2 = 5 L * (640 K / 360 K)

V2 = 8.89 L

Therefore, the container's new volume must be approximately 8.89 liters.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.