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A container with a volume of #17 L# contains a gas with a temperature of #290^o C#. If the temperature of the gas changes to #580 ^o K# without any change in pressure, what must the container's new volume be?

Answer 1

Layla Ahmed

The new volume is #=17.51L#

Charles' Law is used.

#V_1/T_1=V_2/T_2#

Initial volume is #V_1=17L#

Initial temperature is #T_1=290+273=563K#

Final temperature is #T_2=580K#

The final volume is

#V_2=T_2/T_1*V_1#

#=580/563*17=17.51L#

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Answer 2

Isabella Alvarez

The container's new volume must be approximately 34 L.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.