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A container with a volume of #12 L# contains a gas with a temperature of #240^o C#. If the temperature of the gas changes to #420 ^o K# without any change in pressure, what must the container's new volume be?

Answer 1

Emily Abbate

The new volume is #=9.82L#

Utilize Charles' Law

#V_1/T_1=V_2/T_2# #"at constant pressure"#

The initial volume is #V_1=12L#

The initial temperature is #T_1=240+273=513K#

T_2=420K is the final temperature.

The last book is

#V_2=T_2/T_1*V_1=420/513*12=9.82L#

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Answer 2

Axel Acevedo

To find the new volume, we use the formula: ( V_2 = \frac{T_2}{T_1} \times V_1 ). Substituting the given values: ( V_2 = \frac{420 , K}{(240 + 273) , K} \times 12 , L ). Solving this equation gives us the new volume, which is approximately ( 20.57 , L ).

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Answer from HIX Tutor

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