# A container with a volume of #12 L# contains a gas with a temperature of #230^o C#. If the temperature of the gas changes to #420 ^o K# without any change in pressure, what must the container's new volume be?

I get approximately

If there is no change in pressure and the number of moles, we may use Charles's law, which states that

or

Plugging in the given values, we find that

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To find the new volume of the gas, use the combined gas law equation: ( V_2 = \frac{{V_1 \times T_2}}{{T_1}} ). Substitute the given values into the equation: ( V_2 = \frac{{12 \times 420}}{{230 + 273.15}} ). Calculate ( V_2 ) to find the new volume of the gas.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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