# A cone has a height of #24 cm# and its base has a radius of #8 cm#. If the cone is horizontally cut into two segments #15 cm# from the base, what would the surface area of the bottom segment be?

:.Pythagoras:

:.*r^2+pi*r*L#

:.S.A.

:.S.A.

:.Total S.A.

:.Pythagoras:

:.S.A. top part

S.A. top part

S.A. top part

S.A. top part

:.S.A. Botom part

The total surface area of the bottom part got to include

the surface area of the circle of the top part.

:.S.A. Botom part:.=28.274+719.183=747.457 cm^2#

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To find the surface area of the bottom segment of the cone after it's horizontally cut 15 cm from the base, we first need to find the slant height of the top part of the cone, which is ( \sqrt{24^2 + 8^2} = 8\sqrt{10} ) cm. Then, using this slant height, the radius of the top part of the cone becomes ( 8\sqrt{10} - 15 ) cm. Now, we calculate the surface area of the bottom segment using the formula for the surface area of a cone, subtracting the surface area of the top part from the whole cone's surface area. This gives us ( \pi(8^2) - \pi(8\sqrt{10} - 15)^2 ) cm(^2). Simplifying this expression gives the surface area of the bottom segment of the cone.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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