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A compound has the empirical formula of #"CH"_2"O"# and a molar mass of 60 g/mole. What is the molecular formula?

Answer 1

Natalie Anton

#"C"_2"H"_4"O"_2#

Empirical formula #"= CH"_2"O"# Empirical formula mass #"= 12g/mol + 2 g/mol + 16 g/mol = 30 g/mol"#

#"Molecular formula mass"/"Empirical formula mass" = "60 g/mol"/"30 g/mol" = 2#

Molecular formula #= 2 × "CH"_2"O" = "C"_2"H"_4"O"_2#

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Answer 2

Wyatt Atkins

The compound's molecular formula is C3H2O₃.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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