A compound containing only carbon and hydrogen is analyzed, and is found to contain 20.11% hydrogen on a mass basis. How can the empirical formula of the compound be calculated?

Answer 1

We assume 100 g of hydrocarbon. The empirical formula is the simplest whole number ratio that defines constituent atoms in a species.

In 100 g hydrocarbon, there are #(20.11*g)/(1.00794*g*mol^(-1)) = 19.95# #mol# #H#, and #(79.89*g)/(12.011*g*mol^(-1)) = 19.95# #mol# #C=6.65*mol# #C#.
We then divide thru by the lowest ratio to give the empirical formula, #CH_3#.
How did I know that #%C# was #79.89#?
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Answer 2

Divide the mass percentage of each element by its molar mass to find the mole ratio, which is then divided by the smallest mole ratio to find the simplest whole-number ratio. This is how the empirical formula of the compound is calculated.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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