A closed rectangular box has a height of 2 feet, a length of 4 feet, and a width of 4 feet. What is the volume of the box? What is the surface area of the box?

Answer 1

Volume #=32 ft^3#
Surface area #=64ft^2#

Let #L, W and H# be the length , width and height of the box, respectively.

Volume of the rectangular box #V=L*W*H#
#=> V=4xx4xx2=32 ft^3#

Surface area of the closed rectangular box :
#A=2# red area #+ #2 yellow area #+ 2# green area
#= 2 * (L*H + W*H + L*W)#
#= 2*(4*2+4*2+4*4)=64 ft^2#

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Answer 2

Mason Adams

To find the volume of the box, multiply its length, width, and height together:

Volume = Length × Width × Height Volume = 4 feet × 4 feet × 2 feet Volume = 32 cubic feet

To find the surface area of the box, you need to calculate the areas of all six faces and then add them together:

Surface Area = 2(Length × Width) + 2(Width × Height) + 2(Length × Height) Surface Area = 2(4 feet × 4 feet) + 2(4 feet × 2 feet) + 2(4 feet × 2 feet) Surface Area = 2(16 square feet) + 2(8 square feet) + 2(8 square feet) Surface Area = 32 square feet + 16 square feet + 16 square feet Surface Area = 64 square feet

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.