# A circuit with a resistance of #8 Omega# has a fuse with a capacity of #5 A#. Can a voltage of #32 V# be applied to the circuit without blowing the fuse?

The fuse should hold.

OHM'S LAW:

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To determine if a voltage of 32 V can be applied to the circuit without blowing the fuse, we can use Ohm's law to calculate the current in the circuit:

[ I = \frac{V}{R} ]

where: ( I ) = current (in amperes) ( V ) = voltage (in volts) ( R ) = resistance (in ohms)

Given: Resistance (( R )) = 8 Ω Voltage (( V )) = 32 V

Substituting the given values into the equation:

[ I = \frac{32 , \text{V}}{8 , \Omega} = 4 , \text{A} ]

Since the calculated current (4 A) is less than the capacity of the fuse (5 A), applying a voltage of 32 V to the circuit will not blow the fuse. Therefore, it is safe to apply a voltage of 32 V to the circuit.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- A charge of #7 C# is at the origin. How much energy would be applied to or released from a # 9 C# charge if it is moved from # (-5, 1 ) # to #(2 ,-1 ) #?

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