# A circuit with a resistance of #8 Omega# has a fuse with a capacity of #3 A#. Can a voltage of #5 V# be applied to the circuit without blowing the fuse?

Yes it can.

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Yes, a voltage of 5 V can be applied to the circuit without blowing the fuse. To determine if the fuse will blow, we can use Ohm's law, which states that ( V = I \times R ), where ( V ) is voltage, ( I ) is current, and ( R ) is resistance. Rearranging the equation to solve for current, we get ( I = V / R ). Plugging in the given values, we find ( I = 5 , \text{V} / 8 , \Omega = 0.625 , \text{A} ). Since the current (0.625 A) is less than the fuse's capacity (3 A), applying a voltage of 5 V will not blow the fuse.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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