A circuit with a resistance of #6 Omega# has a fuse with a capacity of #5 A#. Can a voltage of #57 V# be applied to the circuit without blowing the fuse?

Answer 1

Emily Abbate

No, the fuse will blow.

What Ohm's Law provides is:

#V=IR#

#:.I=V/R=57/6=9.5"A"#

So you can see that too much current will be drawn through the fuse which is only rated at #6Omega# so it will blow.

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Answer 2

Nathan Ashcroft

Yes, a voltage of 57 V can be applied to the circuit without blowing the fuse. (V = IR, where V is voltage, I is current, and R is resistance. In this case, V = 57 V, R = 6 Ω, so I = V/R = 57 V / 6 Ω = 9.5 A, which is less than the fuse capacity of 5 A.)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.