A circuit with a resistance of #6 Omega# has a fuse that melts at #8 A#. Can a voltage of #49 V# be applied to the circuit without blowing the fuse?

Answer 1

Yes, a voltage of 49 V can be applied to the circuit without blowing the fuse. Since the resistance of the circuit is 6 Ω and the fuse melts at 8 A, using Ohm's law (V = IR), we can calculate the maximum current the circuit can handle without blowing the fuse: I = V/R = 49 V / 6 Ω = 8.17 A, which is less than the fuse rating of 8 A. Therefore, the fuse will not blow with a voltage of 49 V applied to the circuit.

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Answer 2

Lily Adams

The fuse will blow out.

#"Current"= "voltage"/"Resistance"# i.e. #I =V/R# so current is #49/6#= #8.16# #A# As current in circuit is #8.16# #A# fuse will blow out.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.