A circuit with a resistance of #6 Omega# has a fuse that melts at #8 A#. Can a voltage of #24 V# be applied to the circuit without blowing the fuse?

Answer 1

Yes, a voltage of 24 V can be applied to the circuit without blowing the fuse. This is because using Ohm's law (V = IR), the current flowing through the circuit would be calculated as 24 V / 6 Ω = 4 A, which is lower than the 8 A threshold at which the fuse melts. Therefore, the fuse will not blow at 24 V.

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Answer 2

Yes; this will not blow the fuse.

Current (#I#) varies directly as Voltage (#V#) and inversely as Resistance (#R#) #color(white)("XXX")I=V/R#
In this case #color(white)("XXX")I=(24 v)/(6 Omega)= 4 ("volts")/(Omega) = 4 " Ampers"#

The fuse won't blow because this is less than the maximum load it can withstand.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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