# A chord with a length of #5 # runs from #pi/4 # to #pi/2 # radians on a circle. What is the area of the circle?

134.066

As shown in the figure ,the length of the chord AB is 5, which runs from

Now, let the radius of the circle be 'r'. In triangle OAB, angle O is

Draw perpendicular OD from O to side AB. This would bisect AB because OAB is an isosceles triangle. This means AD=BD= 2.5. Since ODB is a rt triangle

= 6.53

Area of circle would be

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The area of the circle can be calculated using the formula for the area of a sector of a circle. Given that the chord length is 5 and it subtends an angle of (\frac{\pi}{4}) to (\frac{\pi}{2}) radians, we can calculate the radius using the formula (r = \frac{c}{2\sin(\frac{\theta}{2})}), where (c) is the chord length and (\theta) is the angle subtended by the chord.

Once we have the radius, (r), we can use the formula for the area of a circle, (A = \pi r^2), to find the area of the circle.

First, calculate the radius using the given chord length and angle subtended. Then, use the radius to find the area of the circle.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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