A charge of #9 C# is passing through points A and B on a circuit. If the charge's electric potential changes from #17 J# to #1 J#, what is the voltage between points A and B?

Answer 1

#16/9# Volts

Voltage = Potential Difference = #"Work Done"/"Charge"# Change in Electric Potential = #delta E# = Work Done by the charge.

So,

Voltage = #(17 - 1)/9# Volts #= 16/9# Volts

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Answer 2

Axel Acevedo

The voltage between points A and B is 2 V.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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