# A charge of #8 C# passes through a circuit every #2 s#. If the circuit can generate #3 W# of power, what is the circuit's resistance?

To find the resistance of the circuit, we can use the formula for power: Power (P) = Current (I) * Voltage (V). Since power is given as 3 W and the current is equal to charge divided by time (I = Q/t), we can rearrange the formula to solve for resistance (R), which is equal to voltage divided by current (V/I).

First, let's find the current (I): I = Q/t I = 8 C / 2 s I = 4 A

Now, let's use the power formula to find the voltage (V): P = I * V 3 W = 4 A * V V = 3 W / 4 A V = 0.75 V

Finally, let's find the resistance (R): R = V / I R = 0.75 V / 4 A R = 0.1875 ohms

Therefore, the circuit's resistance is 0.1875 ohms.

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I found:

using the last one:

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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