A charge of #8 C# passes through a circuit every #12 s#. If the circuit can generate #12 W# of power, what is the circuit's resistance?

Answer 1

#R=27" " Ohm#

#I=(Delta Q)/(Delta t)" Electric Current"# #I=8/12=2/3 A# #P=I^2*R" P:Power;R:Resistance;I:Electric Current"# #12=(2/3)^2*R# #cancel(12)=cancel(4)/9.R# #3=R/9# #R=3*9# #R=27" " Ohm#
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Answer 2

The circuit's resistance can be calculated using the formula for power in terms of resistance and current:

P = I^2 * R

Where:

  • P is the power (given as 12 W)
  • I is the current, which can be calculated as the charge passing through the circuit per unit time (q/t)
  • R is the resistance

Given that the charge q = 8 C passes through the circuit every 12 s, the current I can be calculated as:

I = q / t = 8 C / 12 s ≈ 0.67 A

Now, we can plug the values of power and current into the power formula to solve for resistance:

12 W = (0.67 A)^2 * R

R = 12 W / (0.67 A)^2

R ≈ 26.9 ohms

So, the circuit's resistance is approximately 26.9 ohms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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