A charge of #8 C# passes through a circuit every #12 s#. If the circuit can generate #12 W# of power, what is the circuit's resistance?
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The circuit's resistance can be calculated using the formula for power in terms of resistance and current:
P = I^2 * R
Where:
- P is the power (given as 12 W)
- I is the current, which can be calculated as the charge passing through the circuit per unit time (q/t)
- R is the resistance
Given that the charge q = 8 C passes through the circuit every 12 s, the current I can be calculated as:
I = q / t = 8 C / 12 s ≈ 0.67 A
Now, we can plug the values of power and current into the power formula to solve for resistance:
12 W = (0.67 A)^2 * R
R = 12 W / (0.67 A)^2
R ≈ 26.9 ohms
So, the circuit's resistance is approximately 26.9 ohms.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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