A charge of #54 C# passes through a circuit every #6 s#. If the circuit can generate #9 W# of power, what is the circuit's resistance?

Answer 1

I found: #0.1 Omega#

Remembering that current is the amount of charge passing in one second we can write: #I=Q/t=54/6=9A# Also, power can be written as: #P=I^2R# rearanging: #R=P/I^2=9/9^2=1/9=0.1Omega#

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Answer 2

Adam Arnold

The circuit's resistance is 1.5 ohms.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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